Fast Math Tricks

Multiplication by 3 Digit Numbers – Vedic Math Tricks

9 min read

In this lesson, you will learn the mental math approach for multiplication by 3 digit numbers. In the previous lesson on two digit multiplication, we looked into the vertical and cross wise technique or the Urdhva Tiryak technique from Vedic Maths. It is the same technique that we are going to extend for multiplication by 3 digits.

The aim of this lesson is to help you multiply 3 digit numbers in your head. Mental computation is feasible if you can multiply from left to right, which reduces the overhead involved due to carry. Since the approach to 3 digit multiplication technique explained in this section involves computing from left to right, it can make a significant difference to our mental computation skills. But remember that multiplication of 3 digit numbers from left to right is not fairly easy, as it requires considerable amount of practice. Please use this lesson as a guide to learn the approach and if you would like to practice, you can consider using our App on Math Tricks.

By the end of this post you will learn the following tricks

  • 3 digit by 1 digit multiplication
  • Multiplying 3 digits by 2 digits
  • 3 digit by 3 digit multiplication trick

Multiplication by 3 digit numbers – Video

The approach involved in multiplication by 3 digit numbers is explained in the videos below with the help of two examples. The first example focuses on multiplying three digit numbers without using carry, while the second number deals with carry.

Multiplication by three digits

As explained in the video above, we are going to use the vertical and cross wise technique of Vedic maths to multiply three digit numbers. This technique helps us easily multiply 3 digit numbers mentally. Now let’s look into this multiplication trick by categorizing the approach to multiplication by 3 digits into following sections:

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  • How to multiply two 3 digit numbers
  • Multiplying 3 digits by 2 digits
  • How to multiply 3 digits by 1 digit

How to multiply two 3 digit numbers

 Here, we explain the 3 digit multiplication trick to calculate the product of two numbers from left to right. However it can also be calculated from right to left as well. But we recommend doing it from left to right, as the idea behind learning these tricks is to help enhance our mental calculation skills. Above all, mental calculation is all about calculating from left to right.

So now, given below is the three digit multiplication approach explained with the help of two examples. The approach illustrated in these examples can be used to multiply any three digit number.

Example 1: Product of 121 and 231

  • In order to carry out the multiplication by 3 digits we will divide the solution into 5 parts. The number of parts here is obtained by 2x$n$-1, where $n$ represents the value in n-digit multiplication. In case of 3 digit multiplication n is 3. Hence,

 121
x 231 
 ————————
? | ? | ? | ? | ?

  • Left most part is obtained by multiplying the left most digits 1 in 121 and 2 in 231 => 1×2 = 2.

 121
x 231 
————————
2 | ? | ? | ? | ?

  • The second part is obtained by cross multiplying between the first two digits 1 and 3 & 2 and 2, then adding the respective products => 1×3 + 2×2 = 7

 121
x 231 
————————
2 | 7 | ? | ? | ?

  • Middle part is obtained by doing a 3 digit cross wise multiplication of 1 and 1, 2 and 3, and 1 and 2, and then adding the respective products => 1×1 + 2×3 + 1×2 = 9

 121
x 231 
————————
2 | 7 | 9 | ? | ?

  • The fourth part is obtained by cross multiplying between the last two digits 2 and 1 & 1 and 3, then adding the respective products => 2×1 + 1×3 = 5

 121
x 231 
————————
2 | 7 | 9 | 5 | ?

  • Right most part is obtained by multiplying the right most digits in both the numbers => 1×1 = 1

 121
x 231 
————————
2 | 7 | 9 | 5 | 1

  • Thus we have the result of multiplication of three digit numbers 121 and 231 is 27951.

Example 2: Product of 415 and 326

  • Similar to example 1 lets find the product by dividing the solution into 5 parts:

 415
x 326 
 ————————
? | ? | ? | ? | ?

  • The first part is obtained by taking the product of 4 and 3 => 4×3 = 12

 415
x 326 
————————
12 | ? | ? | ? | ?

  • Now, the next part is obtained by doing a cross multiplication between the first two digits 4 and 2 & 1 and 3, then adding the respective products => 4×2 + 1×3 = 11

 415
x 326 
————————
12 | 11 | ? | ? | ?

Note: Except for the left most part, all the other parts must contain only one digit, the excess digit if any will be carried over to the left. Hence , the excess 1 in 11 will be carried over to the left part. Thus:

 415
x 326 
————————
13 | 1 | ? | ? | ?

  • Next the third part is obtained by doing a 3 digit cross wise multiplication of 4 and 6, 1 and 2, and 5 and 3, and adding the respective products => 4×6 + 1×2 + 5×3 = 41

 415
x 326 
————————
13 | 1 | 41 | ? | ?

=> 13 | 5 | 1 | ? | ?

  • Now, the fourth part is calculated by cross multiplying between the last two digits 1 and 6 & 5 and 2, then adding the respective products => 1×6 + 5×2 = 16

 415
x 326 
————————

13 | 1 | 41 | 16 | ?

=> 13 | 5 | 2 | 6 | ?

  • Last part is obtained by multiplying the right most digits in both the numbers => 5×6 = 30

 416
x 326 
————————
13 | 5 | 2 | 6 | 30

 = 13 | 5 | 2 | 9 | 0

  • Thus we have calculated the 3 digit multiplication of 416 and 326 using the vertical and cross wise technique from left to right without the use of calculator.

Multiplying Three digits by Two digits

 Here, we explain the 3 digit multiplication trick to calculate the product of two numbers from left to right. However it can also be calculated from right to left as well. But we recommend doing it from left to right, as the idea behind learning these tricks is to help enhance our mental calculation skills. Above all, mental calculation is all about calculating from left to right.

So now, given below is the three digit multiplication approach explained with the help of two examples. The approach illustrated in these examples can be used to multiply any three digit number.

Example 1: Product of 121 and 231

  • In order to carry out the multiplication by 3 digits we will divide the solution into 5 parts. The number of parts here is obtained by 2x$n$-1, where $n$ represents the value in n-digit multiplication. In case of 3 digit multiplication n is 3. Hence,

 121
x 231 
 ————————
? | ? | ? | ? | ?

  • Left most part is obtained by multiplying the left most digits 1 in 121 and 2 in 231 => 1×2 = 2.

 121
x 231 
————————
2 | ? | ? | ? | ?

  • The second part is obtained by cross multiplying between the first two digits 1 and 3 & 2 and 2, then adding the respective products => 1×3 + 2×2 = 7

 121
x 231 
————————
2 | 7 | ? | ? | ?

  • Middle part is obtained by doing a 3 digit cross wise multiplication of 1 and 1, 2 and 3, and 1 and 2, and then adding the respective products => 1×1 + 2×3 + 1×2 = 9

 121
x 231 
————————
2 | 7 | 9 | ? | ?

  • The fourth part is obtained by cross multiplying between the last two digits 2 and 1 & 1 and 3, then adding the respective products => 2×1 + 1×3 = 5

 121
x 231 
————————
2 | 7 | 9 | 5 | ?

  • Right most part is obtained by multiplying the right most digits in both the numbers => 1×1 = 1

 121
x 231 
————————
2 | 7 | 9 | 5 | 1

  • Thus we have the result of multiplication of three digit numbers 121 and 231 is 27951.

Example 2: Product of 415 and 326

  • Similar to example 1 lets find the product by dividing the solution into 5 parts:

 415
x 326 
 ————————
? | ? | ? | ? | ?

  • The first part is obtained by taking the product of 4 and 3 => 4×3 = 12

 415
x 326 
————————
12 | ? | ? | ? | ?

  • Now, the next part is obtained by doing a cross multiplication between the first two digits 4 and 2 & 1 and 3, then adding the respective products => 4×2 + 1×3 = 11

 415
x 326 
————————
12 | 11 | ? | ? | ?

Note: Except for the left most part, all the other parts must contain only one digit, the excess digit if any will be carried over to the left. Hence , the excess 1 in 11 will be carried over to the left part. Thus:

 415
x 326 
————————
13 | 1 | ? | ? | ?

  • Next the third part is obtained by doing a 3 digit cross wise multiplication of 4 and 6, 1 and 2, and 5 and 3, and adding the respective products => 4×6 + 1×2 + 5×3 = 41

 415
x 326 
————————
13 | 1 | 41 | ? | ?

=> 13 | 5 | 1 | ? | ?

  • Now, the fourth part is calculated by cross multiplying between the last two digits 1 and 6 & 5 and 2, then adding the respective products => 1×6 + 5×2 = 16

 415
x 326 
————————

13 | 1 | 41 | 16 | ?

=> 13 | 5 | 2 | 6 | ?

  • Last part is obtained by multiplying the right most digits in both the numbers => 5×6 = 30

 416
x 326 
————————
13 | 5 | 2 | 6 | 30

 = 13 | 5 | 2 | 9 | 0

  • Thus we have calculated the 3 digit multiplication of 416 and 326 using the vertical and cross wise technique from left to right without the use of calculator.

Three digit by One digit Multiplication Trick

 

 Here, we explain the 3 digit multiplication trick to calculate the product of two numbers from left to right. However it can also be calculated from right to left as well. But we recommend doing it from left to right, as the idea behind learning these tricks is to help enhance our mental calculation skills. Above all, mental calculation is all about calculating from left to right.

So now, given below is the three digit multiplication approach explained with the help of two examples. The approach illustrated in these examples can be used to multiply any three digit number.

Example 1: Product of 121 and 231

  • In order to carry out the multiplication by 3 digits we will divide the solution into 5 parts. The number of parts here is obtained by 2x$n$-1, where $n$ represents the value in n-digit multiplication. In case of 3 digit multiplication n is 3. Hence,

 121
x 231 
 ————————
? | ? | ? | ? | ?

  • Left most part is obtained by multiplying the left most digits 1 in 121 and 2 in 231 => 1×2 = 2.

 121
x 231 
————————
2 | ? | ? | ? | ?

  • The second part is obtained by cross multiplying between the first two digits 1 and 3 & 2 and 2, then adding the respective products => 1×3 + 2×2 = 7

 121
x 231 
————————
2 | 7 | ? | ? | ?

  • Middle part is obtained by doing a 3 digit cross wise multiplication of 1 and 1, 2 and 3, and 1 and 2, and then adding the respective products => 1×1 + 2×3 + 1×2 = 9

 121
x 231 
————————
2 | 7 | 9 | ? | ?

  • The fourth part is obtained by cross multiplying between the last two digits 2 and 1 & 1 and 3, then adding the respective products => 2×1 + 1×3 = 5

 121
x 231 
————————
2 | 7 | 9 | 5 | ?

  • Right most part is obtained by multiplying the right most digits in both the numbers => 1×1 = 1

 121
x 231 
————————
2 | 7 | 9 | 5 | 1

  • Thus we have the result of multiplication of three digit numbers 121 and 231 is 27951.

Example 2: Product of 415 and 326

  • Similar to example 1 lets find the product by dividing the solution into 5 parts:

 415
x 326 
 ————————
? | ? | ? | ? | ?

  • The first part is obtained by taking the product of 4 and 3 => 4×3 = 12

 415
x 326 
————————
12 | ? | ? | ? | ?

  • Now, the next part is obtained by doing a cross multiplication between the first two digits 4 and 2 & 1 and 3, then adding the respective products => 4×2 + 1×3 = 11

 415
x 326 
————————
12 | 11 | ? | ? | ?

Note: Except for the left most part, all the other parts must contain only one digit, the excess digit if any will be carried over to the left. Hence , the excess 1 in 11 will be carried over to the left part. Thus:

 415
x 326 
————————
13 | 1 | ? | ? | ?

  • Next the third part is obtained by doing a 3 digit cross wise multiplication of 4 and 6, 1 and 2, and 5 and 3, and adding the respective products => 4×6 + 1×2 + 5×3 = 41

 415
x 326 
————————
13 | 1 | 41 | ? | ?

=> 13 | 5 | 1 | ? | ?

  • Now, the fourth part is calculated by cross multiplying between the last two digits 1 and 6 & 5 and 2, then adding the respective products => 1×6 + 5×2 = 16

 415
x 326 
————————

13 | 1 | 41 | 16 | ?

=> 13 | 5 | 2 | 6 | ?

  • Last part is obtained by multiplying the right most digits in both the numbers => 5×6 = 30

 416
x 326 
————————
13 | 5 | 2 | 6 | 30

 = 13 | 5 | 2 | 9 | 0

  • Thus we have calculated the 3 digit multiplication of 416 and 326 using the vertical and cross wise technique from left to right without the use of calculator.

What Next?

As you can see in this lesson, a three digit multiplication is a simple extension of the two digit multiplication trick. This trick requires a considerable amount of practice. But once mastered, you would be amazed with how good a mental workout it would turn out to be. For practise, you can start with 3 digit by 1 digit multiplication from left to right which will help you practise calculating carry mentally and then start with 3 digit by 3 digit multiplication.

Remember, you won’t be able to master left to multiplication over night but by putting in a considerable amount of effort you will definitely fall in love with this technique. Now take the quiz below and the exercises associated with this lesson to get started.

Quiz: 3 Digit multiplication with answers

Practice

Three digit multiplication

5 questions

  1. Find the number of parts in multiplication by 3 digits using the vertical and cross-wise technique as explained above?
    • 3
    • 4
    • 5
    • 6
    Show the answer

    Answer: 5

    The number of parts in 3 digit multiplication using the vertical and cross wise technique is 5.

    In general, the number of parts in an n-digit vertical and cross wise multiplication is given by 2xn-1. 

    Once we calculate the number of parts, we can compute the values of each part either from left to right or from right to left. If you are looking to enhance your mental computation skills, then practise mutliplication from left to right as this makes it calculate when carry is involved.

  2. Find the result of 3 digit multiplication of 121 and 311
    • 35612
    • 37631
    • 35731
    • 37412
    Show the answer

    Answer: 37631

    121 x 311 =>

    Step 1: In order to carry out the multiplication by 3 digits we will first divide the solution into 5 parts => ? | ? | ? | ? | ?

    Step 2: The left most part is obtained by multiplying the hundreds digits 1 in 121 and 3 in 311 => 1x3 = 3
    Thus we have 121x311 => 3 | ? | ? | ? | ?

    Step 3: The next part is obtained by cross-multiplying the digits in hundreds and tens place => 1x1 + 2x3 = 7.
    121x311 => 3 | 7 | ? | ? | ?

    Step 4: The middle part is obtained by doing a 3 digit cross wise multiplication of 1 and 1, 2 and 1, and 1 and 1 => 1x1 + 2x1 + 3x1 = 6
    121x311 => 3 | 7 | 6 | ? | ?

    Step 4: The fourth part is obtained by cross-multiplying the digits in tens and units place => 2x1 + 1x1 = 3
    121x311 => 3 | 7 | 6 | 3 | ?

    Step 5: The right most part is obtained by taking the product of unit digits 1 and 1 => 1x1 = 1.
    121x311 => 3 | 7 | 6 | 3 | 1

    Thus the 3 digit multiplication of 121 and 311 is 37631

  3. Find the product of 132 and 123
    • 15326
    • 15623
    • 16236
    • 15263
    Show the answer

    Answer: 16236

    132 x 123 =>

    Step 1: The process to multiplication by 3 digits will have 5 parts => ? | ? | ? | ? | ?

    Step 2: The left most part => 1x1 = 1
    Thus we have 132 x 123 => 1 | ? | ? | ? | ?

    Step 3: The second part => 1x2 + 3x1 = 5
    132 x 123 => 1 | 5 | ? | ? | ?

    Step 4: The middle part => 1x3 + 3x2 + 2x1 = 11
    132 x 123 => 1 | 5 | 11 | ? | ?

    Note that in 3 digit multiplication using the vertical and cross wise technique, except for the left most part all the other parts must only contain single digit. Hence the excess 1 in 11 will be carried to the left.
    Thus 132 x 123 => 1 | 6 | 1 | ? | ?

    Step 4: The fourth part => 3x3 + 2x2 = 13
    132 x 123 => 1 | 6 | 1 | 13 | ?

    The excess 1 in 13 will be carried to the left.
    132 x 123 => 1 | 6 | 2 | 3 | ?

    Step 5: The right most part => 2x3 = 6.
    132 x 123 => 1 | 6 | 2 | 3 | 6

    Hence the mutiplication of 3 digit numbers 132 and 123 is 16236

  4. Find the value of 432 x 513 using the 3 digit multiplication technique explained above.
    • 2201616
    • 221616
    • 224656
    • 204656
    Show the answer

    Answer: 221616

    432 x 513 =>

    Step 1: The left to right 3 digit multiplcation approach will have 5 parts => ? | ? | ? | ? | ?

    Step 2: The left most part => 4x5 = 20
    Thus we have 432 x 513 => 20 | ? | ? | ? | ?

    Step 3: The second part => 4x1 + 5x3 = 19
    432 x 513 => 20 | 19 | ? | ? | ?

    The excess 1 in 19 will be carried to the left.
    432 x 513 => 21 | 9 | ? | ? | ?

    Step 4: The middle part => 4x3 + 3x1 + 2x5 = 25
    432 x 513 => 21 | 9 | 25 | ? | ?

    Carry the excess 2 in 25 to its immediate left part.
    432 x 513 => 21 | 11 | 5 | ? | ?

    Since the carry from middle part to the second part results in excess digit, the excess digit from second part will be carried to its immediate left.

    432 x 513 => 22 | 1 | 5 | ? | ?

    Step 4: The fourth part => 3x3 + 2x1 = 11
    432 x 513 => 22 | 1 | 5 | 11 | ?

    The excess 1 in 11 will be carried to the left.
    432 x 513 => 22 | 1 | 6 | 1 | ?

    Step 5: The right most part => 2x3 = 6.
    432 x 513 => 22 | 1 | 6 | 1 | 6

    Thus the result of 432 x 513 using the multiplication by 3 digit technique is 221616

  5. Multiply 3 digits by 2 digits : 456 x 21
    • 9576
    • 8476
    • 9566
    • 10566
    Show the answer

    Answer: 9576

    456 x 21 =>

    Multiplying 3 digits by 2 digits involves converting to mutiplication by 3 digits vertical and cross wise technique by prepending 21 with 0.

    Hence, 456 x 21 => 456 x 021 = 9576

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